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1.412÷113+213−34\displaystyle 4\frac{1}{2} \div 1\frac{1}{3} + 2\frac{1}{3} - \frac{3}{4}

Worked solution · Mathematics

412÷113+213−34\displaystyle 4\frac{1}{2} \div 1\frac{1}{3} + 2\frac{1}{3} - \frac{3}{4}

  1. Turn the mixed numbers into improper fractions

    92÷43+73−34\displaystyle \frac{9}{2} \div \frac{4}{3} + \frac{7}{3} - \frac{3}{4}

  2. Divide by multiplying by the reciprocal

    92×34=278\displaystyle \frac{9}{2} \times \frac{3}{4} = \frac{27}{8}

  3. Put everything over 24, then add and subtract

    8124+5624−1824=11924\displaystyle \frac{81}{24} + \frac{56}{24} - \frac{18}{24} = \frac{119}{24}

Answer42324\displaystyle 4\frac{23}{24}

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